Need help, whats the prblm with this code

[Ridaan_ahmed]

[Foxyblack]

Which part are you in?

[Ridaan_ahmed]

All done ,it is showing mapstring is called over 500 times… Help me

[Foxyblack]

but I don’t even know which part you are in, so I can help you

[Daians_Santos]

Qual o problema com essa parte do código?

If( Space.length !== word.length){
return false;
}
For( let i=0 . i < space.length; i ++) {
If ( space [i] ! == “_”&& space [i] !== word [i] ) {
return false;
}
}
return true;

[Lauro_Miranda]

I will try for this example
But I cant

[Lauro_Miranda]

Tentei da mesma forma que voce mas nao tou conseguindo

[Daians_Santos]

Estou com problema no verificador de palavras vc pode me ajudar?

[Vivek_Kumar]

Hmmm i se money height-weaght

[stweffy_88]

If you are following the steps provided by the String Cartography explainer, then they have named their variables slightly differently to the starter code provided when you start this puzzle.

There are two pathways to fix this code:

1. Consistently use map as the variable throughout.
   

   

2. Or use stringMap as the variable instead.
   

   

Note: I use word as a variable instead of string as suggested by the explainer post.

@grasshopperexplainer

Then, add a classic for loop to iterate through the string.

for (let i = 0; i < string.length; i++) {

}

Inside the for loop, create another local variable to store the current character. For example:

let letter = string[i];

Then, use an if else statement (a ternary can also be used) to check if a property already exists in map for the current letter. If the property does not exist, it will be undefined, which is falsy . The if else statement will look something like this:

if (map[letter]) {

} else {

}

If the property already exists (meaning the current character has been seen before), then push the index of the current character to the array contained in the property. If it does not exist, create the array (with the index inside as the 1st item). It should look something like this:

if (map[letter]) {
  map[letter].push(i);
} else {
  map[letter] = [i];
}